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Solve for b

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2 Answers

Hi Lila;
(B+2)(b-3)=-6
I am assuming that B and b are the same and this is just a typographical error.
(b+2)(b-3)=-6
Let's FOIL...
FIRST...(b)(b)=b2
OUTER...(b)(-3)=-3b
INNER...(2)(b)=2b
LAST...(2)(-3)=-6
b2-3b+2b-6=-6
b2-b-6=-6
Let's add 6 to both sides...
b2-b-6+6=-6+6
b2-b=0
b(b-1)=0
b=0, and/or (b-1)=0, b=1.
 
Let's check our work...
b=0
(b+2)(b-3)=-6
(0+2)(0-3)=-6
(2)(-3)=-6
-6=-6
 
b=1
(1+2)(1-3)=-6
(3)(-2)=-6
-6=-6
is the B different than b or are those the same variable. if they are then you would expand the equation to b^2 + b -6 = -6 then solve for b which would give you 0 and 1. if they are not the same then you would need to move things around and get -6/(B+2) + 3= b.