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How do you graph 2x^2+x-14?

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1 Answer

Hi La;
f(x)=2x2+x-14
The parabola opens upward.  We know that because the coefficient of x2 is positive.
We need to know where the vertex is...
Vertex is -b/2a
-1/[(2)(2)]
-1/4
x=-1/4
Let's establish the value of y...
y=2x2+x-14
y=[(2)(-1/4)2]+(-1/4)-14
y=[(2)(1/16)]-(1/4)-14
y=(1/8)-(1/4)-14
y=(1/8)-(2/8)-14
y=(-1/8)-14
y=-14 1/8
vertex is (-1/4, -14 1/8)
 

Comments

Thank you Vivian, but could you help me in graphing it? I know that the vertex is (-0.3, -14.1) but I don't know how to graph parabola.

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