I have to graph Parabolas for my algebra class and I totally forgot. Help Please!!!

## How do you graph 2x^2+x-14?

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# 1 Answer

Hi La;

f(x)=2x

^{2}+x-14The parabola opens upward. We know that because the coefficient of x

^{2}is positive.We need to know where the vertex is...

Vertex is -b/2a

-1/[(2)(2)]

-1/4

x=-1/4

Let's establish the value of y...

y=2x

^{2}+x-14y=[(2)(-1/4)

^{2}]+(-1/4)-14y=[(2)(1/16)]-(1/4)-14

y=(1/8)-(1/4)-14

y=(1/8)-(2/8)-14

y=(-1/8)-14

y=-14 1/8

vertex is (-1/4, -14 1/8)

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