solve the logarithmic equation. Log(4x^2) = 1 (Round to the nearest hundredth as needed. Use a comma to sepreate answers as needed) Feb 21 | Keith from Gresham, OR | 2 Answers | 0 Votes Mark favorite Subscribe Comment
Log 4X^2 = 1 = log 10 4 X^2 = 10 X^2 = 10/4 X = ±√(10) / 2 Feb 21 | Parviz F. Comment Comments Argument to log can't be negative, Parviz. Feb 21 | Steve S. Comment
log(4x^2) = 1 4x^2 > 0 => x > 0 10^1 = 4x^2 x^2 = 10/4 = 5/2 x = √(5/2) ≈ 1.58113883008419 ≈ 1.58 Feb 21 | Steve S. Comment
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