-3<x−1≤2

## how do you graph this inequality

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# 2 Answers

-3 < x−1 ≤ 2

Add 1 to each of the 3 parts:

-2 < x ≤ 3

<----O========@----->

-2 3

This is a single variable graph on a single number line. There is a open dot at -2 and a closed dot at 3.

I'm not sure what all the other discussion is about.

Simple problem, as I see it.

# Comments

thank you so much u got to the point and i wasn't confusing thanks for that

Hi Fanny;

**BELOW, PLEASE FIND THE INSTRUCTIONS ON HOW TO GRAPH THIS. IT WILL REQUIRE ONE VERTICAL DOTTED LINE AT -2=x AND ONE VERTICAL SOLID, NON-DOTTED LINE AT x=3, AND YOU WILL SHADE THE AREA BETWEEN.**

-3<x−1≤2

I would separate this into two equations...

-3<x−1

-2<x

**To graph this, you will draw a vertical, dotted line at x=-2.**

x−1≤2

x≤3

**To graph this, you will draw a vertical, solid, non-dotted line at x=3.**

**You will shade the area between such lines.**

******PLEASE LET ME KNOW IF YOU NEED ADDITIONAL HELP.********

# Comments

i already seperated this into 2 equations and i got -3<x-l which i solved to -2=x and the other equation of x-l≤2 and i got x≤3 but i dont know how to graph it i still dont understand can u please explain a little more thoroughly please thank you

i still dont get it

Do you know what is meant by a vertical line?

i get it now thank you

## Comments

^{2}-2y+y^{2}-8y-2 i got 4y^{2}-10y-2^{2}-5y-1)^{2}^{2}-4x+6x-3^{2}+2x-3^{2 }and the same with 40b^{3}c^{6 }over -8b^{2}c^{2}=(-6a+b)(-6a+b)^{2}^{2}^{2}-6ab-6ab+b^{2}^{2}-12ab+b^{2}^{3}c^{6})/(-8b^{2}c)^{3}/b^{2}=b^{1}=b, because 3-2=1^{6}/c=c^{6}/c^{1}=c^{5}, because 6-1=5^{5}Comment