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## how do you graph this inequality

-3<x−1≤2

turns out i figured it out my self thanks anyway
I am worried about you.  What did you figure-out?
y r u worried i got the answer ... i could understand it
I am glad.  Please let me know if you need anything else.
is this right umm ..... i have to simplify 3y2-2y+y2-8y-2 i got 4y2-10y-2
That is correct.
You can go a one step further...
2(2y2-5y-1)

thank you
im not sure about his problem you also have to simplify
(4x+3)(2x-1) is the answer 8x-3
FOIL...
FIRST...(4x)(2x)=8x2
OUTER..(4x)(-1)=-4x
INNER...(3)(2x)=6x
LAST...(3)(-1)=-3
8x2-4x+6x-3
8x2+2x-3
srry im asking for so much hep but can u also help me by simplifying (-6a+b)and the same with 40b3cover -8b2c
(-6a+b)2=(-6a+b)(-6a+b)
FOIL...
FIRST...(-6a)(-6a)=36a2
OUTER...(-6a)(b)=-6ab
INNER...(b)(-6a)=-6ab
LAST...(b)(b)=b2
36a2-6ab-6ab+b2
36a2-12ab+b2

(40b3c6)/(-8b2c)
40/-8=-5
b3/b2=b1=b, because 3-2=1
c6/c=c6/c1=c5, because 6-1=5
-5bc5
how would u solve for x?
x/x+5 = 1/2
I am assuming this is..
x/(x+5)=1/2
Cross-multiply...
(1)(x+5)=2x
x+5=2x
Subtract x from both sides...
x+5-x=2x-x
5=x
x over x+5=1 over 2
I read it correctly.
x=5
5 over 5+5=1 over 2
5/10=1/2
ur answer doesnot make sense because if substract x from both sides it will be 5=2 and thats not true
you have .....
x+5-x=2x-x
5=x
but...
x+5-x=2x-x
5=2
?????????

Hi Fanny;
Could you please post this as a separate question on Wyzant?  We are confusing other tutors such as Steve.
any way i have another one
the sales tax collected on each sale varies directly as the amount of the sale. What is the constant of varation if a sale tax of \$0.63 is collected on a sale of \$9.00?
ok i guess
0.63/9.00=0.07=7%

-3 < x−1 ≤ 2

Add 1 to each of the 3 parts:

-2 < x ≤ 3

<----O========@----->
-2                   3

This is a single variable graph on a single number line. There is a open dot at -2 and a closed dot at 3.

I'm not sure what all the other discussion is about.

Simple problem, as I see it.

thank you so much u got to the point and i wasn't confusing thanks for that
Hi Fanny;
BELOW, PLEASE FIND THE INSTRUCTIONS ON HOW TO GRAPH THIS.  IT WILL REQUIRE ONE VERTICAL DOTTED LINE AT -2=x AND ONE VERTICAL SOLID, NON-DOTTED LINE AT x=3, AND YOU WILL SHADE THE AREA BETWEEN.
-3<x−1≤2
I would separate this into two equations...

-3<x−1
-2<x
To graph this, you will draw a vertical, dotted line at x=-2.

x−1≤2
x≤3
To graph this, you will draw a vertical, solid, non-dotted line at x=3.

You will shade the area between such lines.

******PLEASE LET ME KNOW IF YOU NEED ADDITIONAL HELP.********