Hi Jhnaesha;
distance...112 miles
Wallace to Vernonville...(x+10) miles/hour
Vernonville to Wallace...x miles/hour
time...1 hour 36 minutes
Our first priority concerns the fact that time is represented in hours and minutes. Speed is represented in miles/hour. Henceforth, we must eliminate the unit of minutes...
(36 minutes)[(1 hour)/(60 minutes)]
The unit of minutes is in the numerator and denominator. It cancels...
(36 minutes)[(1 hour)/(60
minutes)]
[(36)(hours)]/60
3/5 hours
0.6 hours
time=1.6 hours
(112 miles)/(1.6 hours)=[(x+10) miles/hour]+(x miles/hour)
The unit of miles/hour is in the numerator and denominators of both sides of the equation. These cancel...
(112 miles)/(1.6
hours)=[(x+10) miles/hour]+(x
miles/hour)
112/1.6=2x+10
70=2x+10
Let's subtract 10 from both sides...
7010=2x+1010
60=2x
Let's divide both sides by 2...
60/2=(2x)/2
30=x
Vernonville to Wallace...30 miles/hour
Wallace to Vernonville...(30 +10) miles/hour=40 miles/hour
Feb 17

Vivian L.