I need homework help and i don't know how to factor with more than one variable.
how do i solve 5ax^2-45a
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Factor with the coefficients first, then factor with the variables one at a time but you only have one variable, a ,
which is in both terms.
The GCF of 5 and 45 is 5.
The GCF of a and a is a
The GCF is 5a.
5ax^2-45a=5a(x^2-9) because 5ax^2/5a=x^2 and -45a/5a=-9
Now x^2-9 can be factored: x^2-9=(x-3)(x+3)
5a X^2 - 45a = 0
5a ( X^2 - 9 ) = 0
Note : You just pull out the GCF, regardless of how many variable contains.
Let's factor-out the a...
Let's factor-out the 5...
Let's factor (x2-9) into two parenthetical expressions.
For the FOIL...
FIRST must be (x)(x)=x2
OUTER and INNER must add-up to 0x or 0.
LAST must be (3)(3) and one 3 must be negative and one must be positive to render the sum of 0 and the product of -9.