Hello again, I'm still figuring out theese sorts of problems, if someone could help me, I would greatly appreciate it. http://prntscr.com/2ryvb1 There's a screenshot of the question

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# 2 Answers

Hi Darian,

1/3(8y-2)+1/9(12y+10)

By using distributive property,we get

8y/3-2/3+12y/9+10/9

8y/3+4y/3-2/3+10/9

12y/3-6/9+10/9

4y+4/9

4(y+1/9)

Hi Darian;

[(1/3)(8y-2)]+[(1/9)(12y+10)]

We would like the denominator in both bracketed equations to be the same.

Let's multiply the first bracketed equation by 3/3

[(3/3)(1/3)(8y-2)]+[(1/9)(12y+10)]

[(3/9)(8y-2)]+[(1/9)(12y+10)]

[(24y/9)-(6/9)]+[(12y/9)+(10/9)]

(36y/9)+(4/9)

4y+(4/9)

or

4[y+(1/9)]