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I need help solving this problem, I have a screenshot provided.

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1 Answer

Hi Darian;
[(1/4)(13y-3)]+[(1/8)(6y+9)]
[(13y/4)-(3/4)]+[(6y/8)+(9/8)]
Multiply first bracketed equation by 2/2 such that both bracketed equations have 8 as a denominator...
{(2/2)[(13y/4)-(3/4)]}+[(6y/8)+(9/8)]
[(26y/8)-(6/8)]+[(6y/8)+(9/8)]
Combine like terms...
(32y/8)+(3/8)
4y+(3/8)

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