I'm having a lot of trouble with this problem, I would like some step by step instructions if possible. I understand all the rest besides this one http://prntscr.com/2ryks4

## I need help solving this problem, I have a screenshot provided.

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# 1 Answer

Hi Darian;

[(1/4)(13y-3)]+[(1/8)(6y+9)]

[(13y/4)-(3/4)]+[(6y/8)+(9/8)]

Multiply first bracketed equation by 2/2 such that both bracketed equations have 8 as a denominator...

[(1/4)(13y-3)]+[(1/8)(6y+9)]

[(13y/4)-(3/4)]+[(6y/8)+(9/8)]

Multiply first bracketed equation by 2/2 such that both bracketed equations have 8 as a denominator...

{(2/2)[(13y/4)-(3/4)]}+[(6y/8)+(9/8)]

[(26y/8)-(6/8)]+[(6y/8)+(9/8)]

Combine like terms...

(32y/8)+(3/8)

4y+(3/8)