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## Museum passes cost $5 for adults and $2 for children. One day the museum sold 1820 passes for $6100. How many of each type were sold?

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# 2 Answers

X - number of children passes sold

1820 - X --- Number of adults passes sold

X ( $2) + ( 1820 - X ) $5 = $6100 ( 1)

Solve for X , in equation ( 1)

2X + 9100 - 5X = 6100

-2X = -9100 + 6100 = -3000

X = 1500 / # of children passes sold

1820 - 1500 = 320 / # of adult passes sold.

Remember always choose a variable for unknown , what problem is asking to find.

**The key to this problem is creating an equation to relate the things you know.**

We know that 1820 passes were sold.

What we don't know yet is how many adult tickets were sold. So let's choose some variable x to represent that quantity.

That means that the remaining tickets, (1820-x), represents the number of children's tickets sold.

You know that the money made from the adult tickets is 5*(num adult tickets sold) and the money from children's tickets is 2*(num children's tickets sold). Moreover you know that the total amount of money made is $6100.

So in summary:

**adult money + childrens money = total money**

adult money = (# adult tickets sold) * 5

children's money = (# children's tickets sold) * 2

total money = 6100

Without giving absolutely everything away, you now have a simple equation with one variable. Solve for x and you have your answer.