Hi Keith;
g(x) = [ 7x  1] + 8
a. g(1)
g(1) = {[(7)(1)]1}+8
g(1)=(71)+8
g(1)=8+8
g(1)=0
b. g(b)
g(b) = [ 7b  1] + 8
c. g(x^3)
g(x^{3}) = [ 7x^{3}  1] + 8
g(x^{3})=7x^{3}1+8
g(x^{3})=7x^{3}+7
d. g(x  7)
g(x7) = {[(7)(x7)]1}+8
g(x7)=7x491+8
g(x7)=7x+56
Feb 4

Vivian L.