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They need to buy 25 more chairs than stools The chairs cost $32 each the stools cost $28 each budget is $2,620, how many chairs can they buy?

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2 Answers

Hi Natalia;
stools...x, $28/stool
chairs...x+25, $32/chair
budget...$2,620
$2620=[($32)(x+25)]+[($28)(x)]
$2620=$32x+$800+$28x
$2620=$60x+$800
Let's subtract $800 from both sides...
$2620-$800=$60x+$800-$800
$1820=$60x
Let's divide both sides by $60...
$1820/$60=($60x)/$60
30=x
30+25=x+25
They can purchase 30 stools, 55 chairs, and will have $20 remaining.
let x=# of stools
let x+25=# of chairs
$28*x+$32*(x+25)=$2620
28x+32x+800=2620
60x+800=2620
60x=1820
x=1820/60
x=30.333...
You can buy 30 stools and 55 chairs.
30*$28+55*$32=$840+$1760=$2600 with $20 left over