I need the answer for my brother i couldn't figure it out.

## They need to buy 25 more chairs than stools The chairs cost $32 each the stools cost $28 each budget is $2,620, how many chairs can they buy?

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# 2 Answers

Hi Natalia;

stools...x, $28/stool

chairs...x+25, $32/chair

budget...$2,620

$2620=[($32)(x+25)]+[($28)(x)]

$2620=$32x+$800+$28x

$2620=$60x+$800

Let's subtract $800 from both sides...

$2620-$800=$60x+$800-$800

$1820=$60x

Let's divide both sides by $60...

$1820/$60=($60x)/$60

30=x

30+25=x+25

They can purchase 30 stools, 55 chairs, and will have $20 remaining.

let x=# of stools

let x+25=# of chairs

$28*x+$32*(x+25)=$2620

28x+32x+800=2620

60x+800=2620

60x=1820

x=1820/60

x=30.333...

You can buy 30 stools and 55 chairs.

30*$28+55*$32=$840+$1760=$2600 with $20 left over