Need the answer. Didn't know on the midterm.
Find x: 3x(x-2)(x+1)+0
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f(x) = 3x(x - 2)(x + 1) = 0
We know that this is true when x = 0, x = 2 and x = -1
The person who gave you this problem is very kind. It is already factored in such a way that the identity of the zeros is manifestly obvious.
3x(x - 2)(x + 1) = 0
if the product is equal to zero, then one of the numbers should be zero. for example:3x2x0=0
So, 3x=0 or x-2=0 or x+1=0