A circular-motion addict of mass 85 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 5.8 m/s.
(a) What is the period of the motion?
(b) What is the magnitude of the normal force on the addict from the seat when both go through the highest point of the circular path?
(c) What is it when both go through the lowest point?
a) period = 2pi r/v = 2pi*10/5.8 = 10.8 sec
b) Draw free body diagram, and apply Newton's second law:
N+mg = mv2/r
N = m(v2/r - g) = 547 N <==Answer
c) Draw free body diagram again, and apply Newton's second law:
N-mg = mv2/r
N = m(v2/r + g) = 1119 N <==Answer