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Find the acceleration vector?

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2 Answers

Position: r = [t2+1, ln(2t+3)]
 
Velocity: v = dr/dt = [2t, 2/(2t+3)]
 
Acceleration: a = dv/dt = [2, -4/(2t+3)²]

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V [(dx/ dt = 2t , dy/dt= 2/ ( 2t+3)] / velocity        
 
 
 
a [ d2x / dt2= 2  , d2y/dt2 = -4/ (2t + 3) ^2
                         
 
 
 Note :  U = ln t    du/dt = 1/t      d2u/dt2 =  -1/ U2