What is the area, please let me know ASAP, can you show me what steps you need to take also when your solving the problem.

## There is a rectangle, it's height is 3x and its width is 2x+xy. Find the area, but in the rectangle there are to empty boxes, there width and hight are x.

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# 1 Answer

Hi Shivansh,

Step 1. If you draw a rectangle, you can label the height as 3x and the width as 2x+xy.

Step 2. The area of the large rectangle is height multiplied by the width: 3x(2x + xy). You can use the distributive property to simplify the terms: 3x(2x) + 3x(xy) = 6x

^{2}+ 3x^{2}y .Step 3. To find the area of the two smaller boxes inside the rectangle, draw a line that separates the width into two parts, so that one part will have a width of 2x and the other part will have a width of xy. The height, 3x, remains the same for both
of the smaller boxes.

Therefore the area of the two boxes will be:

3x(2x) = 6x

^{2 }and 3x(xy) = 3x^{2}y, which are identical to the terms created when we distributed in step 2.Hope that helps.

## Comments

^{2}+ 3x^{2}y .Comment