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# How do you find the slope intercept form

y= -x +1

I have a x and y table.

That is the problem that  i need to solve. Could someone help me figure it out asap.

two points on the line could be (2,-1) and (3,-2). to find the slope you can use the equation

m=(y2-y1)/(x2-x1)= (-2-(-1))/(3-2)=(-2+1)/(3-2)= -1/1= -1. to find the x-intercept we let y=0 in

the equation and get x=1. if you want to find the y-intercept you can let x=0 in the equation and

I'm not quite sure what you are asking for. But, the slope intercept form is y=mx+b, where m is the slope of the line, b is the y-intercept, and x and y are the respective coordinates for that line. if you are given two points on a line, for example (1,2) and (2,3) you can find the slope intercept form of the line that runs through those points by first finding the slope, using

m=(y1-y2)/(x1-x2)

m=(1-2)/(2-3)=(-1)/(-1)=1

So in out equation we now have m. Next to find the y-intercept we substitute the slope we found and one of the given points in y=mx+b, to yield 2=1(2)+b, and solve:

2=2+b

2-2=b

so b=0

and we can now write the equation for the line;

y=1x+0 or y=x.