Hi T;
[(3t+2)/7]+[(t4)/14]
The first priority is to have both denominators, also known as divisors, identical. One is 7, the other 14. Let's take the fraction with the former divisor and multiply it by 2/2.
(2/2)[(3t+2)/7]
[2(3t+2)]/14
[2(3t+2)]/14+[(t4)/14]
Let's combine the two numerators, information on top of each fraction.
[2(3t+2)+(t4)]/14
Now, let's distribute the 2...
(6t+4+t4)/14
6t+t=6t+1t=7t
44=0
7t/14
7/14=1/2
1t/2
t/2
Jan 24

Vivian L.