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Factor. s^2(t - u) - 9t^2 (t - u)

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2 Answers

Corry,
 
the common factor for both are (t-u), we can take it out:
 
(t-u)(s^2-9t^2)
 
And because a^2-b^2=(a+b)(a-b), in this case,
 
 s^2-9t^2
=s^2-(3t)^2   [note: s=a, 3t=b in the above formula]
=(s+3t)(s-3t)
 
So the complete factor for this one is (t-u)(s+3t)(s-3t)
 
Hope it helps.
 
Heng