Math homework, please help!

## whats an equation perpendicular to x+y=6 and passes through (2, 8)

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# 1 Answer

Re-working the equation by subtracting x from both sides gives:

y = -x + 6 With a slope of -1

Perpendicular slopes are the negative reciprocal of the initial slope

-1/-1=1

y = x + k is our new equation, with some displacement "k"

Using point slope formula, y-y

_{1 }= m(x-x_{1})y - 8 = 1*(x-2)

Add 8 to both sides and distribute the right side

y = x + 6 , or -x + y = 6

## Comments

Thank You so much! I actually have A few more questions l think you might be able to help Me With

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