Math homework, please help!
whats an equation perpendicular to x+y=6 and passes through (2, 8)
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Re-working the equation by subtracting x from both sides gives:
y = -x + 6 With a slope of -1
Perpendicular slopes are the negative reciprocal of the initial slope
y = x + k is our new equation, with some displacement "k"
Using point slope formula, y-y1 = m(x-x1)
y - 8 = 1*(x-2)
Add 8 to both sides and distribute the right side
y = x + 6 , or -x + y = 6