Find the equation of a line through the points (-2,1) and (3,6)

## Find the equation of a line through the points (-2,1) and (3,6)

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# 2 Answers

Hi John;

(-2,1) and (3,6)

First, let's establish slope.

Slope is the change-of-y divided by the change-of-x.

slope=(y-y

_{1})/(x-x_{1})slope=(1-6)/(-2-3)

slope=-5/-5

slope=1

Let's take one point and use the point-slope formula. I randomly select the first point, (-2,1)

y-y

_{1}=m(x-x_{1})y-1=1(x--2)

Subtracting a negative number is the same as adding a positive number...

y-1=x+2

Let's add 1 to both sides...

1+y-1=x+2-1

**y=x+3**

Let's apply the other point, (3,6), to verify...

6=3+3

6=6

First of all, you find the slope of the line, by finding, (the distance in y)/(the distance in x)= (6-1)/(3-(-2))=? (I think you should do that yourself, this is easy).

After you find the slope, say its a value, called a. You will insert a, into the slope-intercept form of the linear equation: y=ax+b. You could use either (-2, 1) as your (x, y), or (3, 6), as your (x, y). Now you know a, x, y, solve for b. This shouldn't
be too hard either. I think you should do it yourself.