9x

^{2}^{ }+ 12xy + ca perfect square trinomial

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9x^{2}^{ }+ 12xy + c

a perfect square trinomial

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Hi Stacy,

(a+b)² = (a)²+2(a)(b)+(b)²^{
}

9x²+12xy+c = (3x)²+2(3x)(2y)+(2y)²

=(3x+2y)²

c=(2y)²=4y²

Hi Stacy;

9x^{2} + 12xy + c

I think this is...

9x^{2} + 12x + c........There is no y...

For the FOIL...

FIRST...(3x)(3x)=9x^{2}

OUTER and INNER must add-up to 12x. Because the coefficient of each x is 3, and because there are 2 parenthetical equations, and because the second number of the parenthetical equation must duplicate, we can calculate this second number of the parenthetical
equations by (3)(2)(?)=12....?=2.

(3x+2)^{2}

(3x+2)(3x+2)

(3x+2)(3x+2)

Let's FOIL...

FIRST...(3x)(3x)=9x^{2}

OUTER...(3x)(2)=6x

INNER...(2)(3x)=6x

LAST...(2)(2)=4

9x^{2}+6x+6x+4

9x^{2}+12x+4

There is a y.... And I don't get it? Plz explain...

If there is a y, then I do not know how to resolve c such that this is a perfect square.

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