an=(2)^{n1}
n  n1  2^{n1}

1  0  1
2  1  2
3  2  4
4  3  8
5  4  16
Note that you did not write the sequence as (2)^{n1.} You wrote it as (2)^n^1, where n^{1} = 1/n^{1} = 1/n. (The superscript feature of this editor does not express a power raised to a power.) However, if this was the intent,
then instead of the above we would actually have:
n  n^{1}  2^n^{1}

1  1  2
2  1/2  2^{1/2} = the square root of 2
3  1/3  2^{1/3} = the cube root of 2
4  1/4  2^{1/4} = the fourth root of 2
5  1/5  2^{1/5} = the fifth root of 2
Jan 12

Kevin F.
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