Hi Katie!
If you start with f(x) = (x+2)^{2}, that's a parabola w/ vertex at (2, 0). If you move the graph 11 units to the right, the vertex will move to the point (9, 0). But that means the equation of the new graph is g(x) = (x9)^{2}. So the
answer is actually 1.
Another way to get this is to replace the x in (x+2)^{2} with x11... (x11 + 2)^{2} > (x9)^{2}. The reason it has to be x11 instead of x+11 has to do with the fact that because you're shifting the graph to the right 11 units,
all the xvalues are getting 11 units larger for the same yvalues. Thus, you have to minus 11 to get back the same xvalues that corresponded with the yvalues you started with. Hopefully that made a third of sense, it's kind of a retribution thing ("you've
increased all my xvalues, now I've gotta take them away so the yvalues don't notice"). Who says math isn't full of drama?? ;)
Jan 12

Murtaza N.
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