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## 3x+4y=8 slope of a perpenciulare lines

Find the slope of a line perpendicular to each given line

Hi Young Friend,
I show you another way for finding slop. If you have Ax+By+C=o that it is one of standard form for line.
It is enough, you find -A/B because it is slop.

3x+4y=8  3x +4y-8=0   slop = -3/4   as you know A=3 , B=4 . Now if you need slop for perpendicular line is
+4/3 and slop for parallel line is  -3/4. In fact when two lines are parallel they have the same slop. I hope this explain is useful for you. Please feel free if you have any question.

Be successful,
Minoo
Hi Aaron;
The equation is currently in standard form...
Ax+By=C, A and B do not equal zero, and A is greater than zero.
The equation must be converted into slope-intercept form...
y=mx+b, m is the slope and b is the y-intercept, the value of y when x=0.
3x+4y=8
4y=-3x+8
y=[(-3/4)x]+2
The slope is -3/4.  The slope of the line perpendicular to such is positive 4/3.
Dear Aaron,

3x + 4y = 8

4y = 8 - 3x

y = 2 - (3/4)x

So the slope of the given line is -(3/4).

The slope of any and all lines perpendicular to the given line is

-[1/(-3/4)] = 4/3

The slope of a line that is perpendicular to another line that has slope m is always -(1/m).

Take it to the bank.