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Find all solutions in the interval [0,2pi): sin2x=cosx

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1 Answer

 Sin 2X = CosX
 
  2 Sinx CosX - CosX =0
 
    CosX ( 2 Sin X - 1 ) =0
 
   Cos X = 0      X = 90° = π/2     or X = 270° = 3π/4
 
 
     2SinX = 1       X = 30° = π/6  or  X = 150° = 5π/6  

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