This is for my trig class. Thanks for the help!

## Rewrite 6(sin5x)cos2x

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# 2 Answers

Using a Product-to-Sum Identity:

6 sin(5x) cos(2x) = 3 [2 sin((7x+3x)/2) cos((7x-3x)/2)

= 3 sin(7x) + 3 sin(3x)

6 sin(5x) cos(2x) = 3 [2 sin((7x+3x)/2) cos((7x-3x)/2)

= 3 sin(7x) + 3 sin(3x)

The reason it's important to do this simplification is that it is MUCH easier to integrate 3 sin(7x) + 3 sin(3x) than the original expression. You'll do this in calculus.

Dear Serenity,

I am confused. I believe 6sin(5x)][cos(2x)] is already as simple as it can be. I mean I suppose you could rewrite it as

6[sin(5x)][1 - sin

^{2}(2x)] (from the double angle formula for cos(2x))but what would be the point? Do you have some particular answer for which you are striving?

Sometimes I think the professors and/or textbook authors who make up problems regarding trigonometric identities have way to much time on their hands!