This is for my trig class. Thanks for the help!
Find all solutions in the interval [0,2pi): tan^2x + (sqrt3-1)tanx-sqrt3 = 0
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(tan x + sqrt3)(tan x - 1) = 0
tan x = -sqrt3, => x = 2pi/3, 5pi/3
tan x = 1, => x = pi/4, 5pi/4
Answer: x = pi/4, 2pi/3, 5pi/4, 5pi/3