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graph the system of inequalities

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 Y≤3/2X + 3
 
 
 
  First graph the line Y = 3/2 X + 3
 
       The intercept points are : ( 0 ,3 )  ,  ( -2 , 0 )
 
      After drawing test a point to the right or left of the line.
 
       ( 0, 0 )
 
             0 ≤ 0 + 3 , therefore the region to the right of the ( -2, 0 ) is the solution, mark it with dash with shade as solution .
    Since there is ≤ the line has to be solid, meaning the points on the lines are the solution.
    without the  = sign then the line would have been drawn as dashed lines.