what does 7x + 9y >=693 look like on a graph
what does 7x + 9y >= 693 look like on a graph
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First let's transform the inequality 7x+ 9y≥693
by subtracting both sides by 7x we have :
Dividing both sides by 9 it comes y≥-7x⁄9+693
let's consider the linear function y=-7x/9+693.
it is a downward line (y-intercept 693).
Therefore, the solution of the inequality 7x+ 9y≥693 is the area of the plane above the line defined by y=-7x/9+693.
7X + 9y ≥ 693
Divide both sides by 63
9x + 7Y ≥ 11
Graph the line 9X + 7Y = 11 , by connecting the intercept points : ( 11/9,0 ), ( 0, 11/7)
Test one point to the left of the line:
say ( 0,0)
Plugging in the inequality:
9(0) + 7(0) = 0 < 11, therefore left side of the line is not the solution.
Mark the right side shaded as the solution.