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what does 7x + 9y >= 693 look like on a graph

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2 Answers

First let's transform the inequality 7x+ 9y≥693
by subtracting both sides by 7x we have :
9y≥-7x+693
Dividing both sides by 9 it comes y≥-7x⁄9+693
let's consider the linear function y=-7x/9+693.
it is a downward line (y-intercept 693). 
Therefore, the solution of the inequality 7x+ 9y≥693 is the area of the plane above the line defined by y=-7x/9+693.

Comments

One slight correction to the above post.  When dividing both sides by 9, don't forget to divide both terms on the right side by 9. 
 
9y≥-7x+693    Now divide both sides by 9.
 
y≥-7x/9+77     So the y -intercept is 77,
 
and the solution is the area of the plane above the line y=-7x/9+77

Comment

 Graphical Solution:
 
    7X + 9y ≥ 693
 
     Divide both sides by 63
 
        9x + 7Y ≥ 11
 
            Graph the line 9X + 7Y = 11 , by connecting the intercept points : ( 11/9,0 ), ( 0, 11/7)
 
         Test one point to the left of the line:
    
            say ( 0,0) 
 
              Plugging in the inequality:
             
              9(0) + 7(0) = 0 < 11, therefore left side of the line is not the solution.
             
               Mark the right side shaded as the solution.