George and Bill left town A for town B at the same time. George was riding a bicycle at a constant speed, while Bill was driving a car. Bill traveled 5 times faster than George. Bill's car broke halfway, and the rest of the way to the town B Bill traveled by foot with a speed equal to half of the George's bicycle speed. Who got to B first: George or Bill?
George Speed - X
Bills Speed - 5X
Bills speed by foot - X/2
d- distance from A-B
X = d/t1 5X + X/2 =d/t2
11X/2 = d/ t2
t1= d/X ---------------- time it takes Bill to go from A to B
t2 = d/ (11X/2)---------- Time it will take George to go from A to B
t1 > t2 , Therefore Bill reaches earlier.
Note : The formula used was
Speed * ( time it would take) = distance traveled.