9 3/4 inches 7 1/3 inches need help with this problem

## a triangle has a perimeter of 24 5/8 inches. what is the lenght of its third side 9 3/4 inches 7 1/3 inches

Tutors, please sign in to answer this question.

# 2 Answers

c = 24 5/8 - 9 3/4 - 7 1/3 =

24 - 9 - 7 +5/8 - 3/4 - 8/3=

8 + 15 /24 -18 /24 -8 /24 =

8 - 11/24= 7 + 24/24 - 11/24 = 7 13/24

This is a hint how to handle addition of mixed numbers, you add integers together, and fractions together.

Hi Richard;

perimeter=(side A)+(side B)+(side C)

24 5/8=(9 3/4)+(7 1/3)+(side C)

Let's get rid of the fractions.

The denominators on the right side are 4 and 3. Let's use the denominator of 12...

(3/4)(3/3)=9/12...side A 9 9/12

(1/3)(4/4)=4/12...side B 7 4/12

24 5/8=(9 9/12)+(7 4/12)+(side C)

24 5/8=(16 13/12)+(side C)

24 5/8=(17 1/12)+(side C)

The denominators are now 8 and 12. Let's convert these to 24...

(5/8)(3/3)=15/24...perimeter=24 15/24

(1/12)(2/2)=2/24...sides A+B=17 2/24

24 15/24=(17 2/24)+(side C)

Let's move 17 2/24 from the right to the left side. It becomes negative...

(24 15/24)-(17 2/24)=side C

7 13/24=side C