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exams scores

. Students in a math class took a final exam and then took equivalent forms of the exam at monthly intervals thereafter. The average score f(t), as a percent, after t months was found to be given by the function f(t)=88-15ln(t+1), 0≤t≤12.

(a) What was the average score on the original exam?
(b) What was the average score after 2 months? 4 months? 6 months? 8 months? 10 months? One year?
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2 Answers

a)
      f(t) = 88 - 15 ln( t+1)
 
      f(0) = 88 - 15 ln1 = 88 - 15(0) = 88
 
  b) f(2) = 88 - 15 ln( 2+1) =
               88 - 15 ln(3) = 86.9
       f(4) = 88 - 15 ln (5) = 88 - 15 ( 1.61) = 63.85
 
       f(6) =
 
      f(8) =
 
       f( 10) =
     
       f(12) =
 

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