If line JL, line DF, and line HI are parallel m<LAB=37.1 and m<ACB=58.6 what is the value for y?

Angles ACB and DGC are on opposite sides of transversal line AC and two parallel lines DF and HI. Thus, angle ACB and DGC are alternate interior angles, therefore measure of angel ACB = measure of angel DGC

m < ACB = m < DGC = 58.6

< CGD and < AGD are supplementary angles -----> m < CGD + m < AGD = 180

m < ACB = m < DGC = 58.6

^{o}< CGD and < AGD are supplementary angles -----> m < CGD + m < AGD = 180

^{o}**m < AGD = 180***y =*^{o}- 58.6^{o}=*121.4*^{o}
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