Find the y-intercept of the tangent line to the curve y=sqrt(x^2+33). The answer is 33/7. Dec 1 | Sun from Los Angeles, CA | 1 Answer | 0 Votes Mark favorite Subscribe Comment
y=sqrt(x^2+33) y' = 2x/[2sqrt(x^2+33)] = 4/7 at x = 4 (Attn: You need to give the point (4, 7)) Equation of tangent line at (4,7), y - 7 = (4/7)(x-4) Let x = 0. You have y-int = 7+(4/7)(-4) = 33/7 <==Answer Dec 1 | Robert J. Comment