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Make y the subject of 4y-2x=17 and 2y over 3-x=z

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1 Answer

Hi again Kath;
4y-2x=17
Let's add 2x to both sides...
2x+4y-2x=2x+17
4y=2x+17
Let's divide both sides by 4...
y=(2x+17)/4
y=(2/4)x+(17/4)
y=(1/2)x+(17/4)
 
2y over 3-x=z
(2y)/(3-x)=z
Let's multiply both sides by (3-x)
(3-x)[(2y)/(3-x)]=z(3-x)
2y=z(3-x)
Let's divide both sides by 2...
(2y)/2=[z(3-x)]/2
y=[z(3-x)]/2