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## solve this equation using the quadratic formula; 2x^2 + x = 15

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# 2 Answers

2x

^{2}+ x = 152x

^{2}+ x - 15 = 0(2x - 5) (x + 3) = 0

If the product of the two expressions is zero, then one or both of the factors must be zero. Find those values of x that make each factor equal to zero:

2x -5 = 0

2x = 5

x = 5/2

x + 3 = 0

x = -3

x = -3, and x = 5/2

ax^2 + bx + c = 0

D = b^2 - 4ac

x

2x^2 + x - 15 = 0

a = 2, b = 1, c = - 15

D = 1 + 120 = 121

x

D = b^2 - 4ac

x

_{12}= (- b ± √D) / 2a2x^2 + x - 15 = 0

a = 2, b = 1, c = - 15

D = 1 + 120 = 121

x

_{12}= (- 1 ± √121) / 4**= (- 1 + 11) / 4 = 5/2***x*_{1}*= 2.5***= (- 1 - 11) / 4***x*_{2}*= - 3*