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Algbrea 2 Math word problem math

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Hi again Bridget;
Now let's do the equation!
y3-14y2+48y=
For the FOIL...
FIRST must be...(y2)(y)=y3
OUTER and INNER must add-up to -14y2
LAST must be (8)(6y) or (8y)(6) or (24)(2y) or (24y)(2) or (16y)(3) or (16)(3), etc. and both numbers must be negative.
(y2-6y)(y-8)
Let's FOIL...
FIRST...(y2)(y)=y3
OUTER...(y2)(8)=-8y2
INNER...(6y)(y)=-6y2
LAST...(-6y)(-8)=48y
y3-8y2-6y2+48y
y3-14y2+48y