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how to graph a linear equation with fractions

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Hi Trinity;
I assume this is...
(-1/2)x + (1/8)y = 3/4
Let's eliminate the fractions...
Let's note the fact that the denominators, also known as divisors, are 2, 8 and 4.  Let's multiply everything by 8...
8[(-1/2)x + (1/8)y] = 8(3/4)
-4x+y=6
If you would like this in the format of y=mx+b such that you can easily graph it, then let's move the -4x from the left side to the right where it becomes positive...
y=4x+6
The slope of this line, change of y divided by change of x, is 4.
The y-intercept, value of y when x=0, is 6.
Does this help, or is there more to this question?
 

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I am still confused.  my book says to subtract to move x to the other side of the equation.  then divide to get y by itself.
Let's do what your book says, almost...
(-1/2)x + (1/8)y = 3/4
Let's add, not subtract, (1/2)x to both sides of the equation...
We must add because the negative (1/2)x is already on the left side of the equation.  We need to cancel it as we proceed to isolate y...
(1/2)x-(1/2)x+(1/8)y=(1/2)x+3/4
(1/8)y=(1/2)x+3/4
Now we can multiply both sides by 8, not divide by 8...
(8)(1/8)y=8[(1/2)x+3/4]
y=4x+6
 
I wish I could see your book.
Can you give me a page number?
Is that the correct page number?
yes, page 97, problem #15 is the one I was doing,  the book is the 8th grade florida, it is blue and white with the kid playing soccer.
I cannot find it using the hyperlink you provided.
How did the test go?

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