solve algebraic equations
the sum of two number is 50.the second number is 8 more than the first number
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Let the first number be x. Then:
the second number becomes x+8.
Set up an equation: x+(x+8)=50 => 2x+8=50 => 2x=42 => x=21 => this is the first number (because this is what we set equal to x)
Second number = x+8 => 21+8=29
Two unknowns x and y.
Using information from the problem
x + y = 50 Sum of two numbers is 50
y = x + 8 The second number is 8 more than the first number.
Replace y in first equation
x + (x+8) = 50
2x + 8 = 50
subtract 8 from both sides
2x = 42
Divide both sides by 2
x = 21
Solve for y
y = 21 + 8 = 29
The two numbers are 21 and 29.
Let's subtract 8 from both sides...
Let's divide both sides by 2...