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the sum of two number is 50.the second number is 8 more than the first number

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3 Answers

Let the first number be x. Then:
the second number becomes x+8.
Set up an equation: x+(x+8)=50 => 2x+8=50 => 2x=42 => x=21 => this is the first number (because this is what we set equal to x)
Second number = x+8 => 21+8=29
Two unknowns x and y.
 
Using information from the problem
 
x + y = 50  Sum of two numbers is 50
y = x + 8  The second number is 8 more than the first number.
 
Replace y in first equation
 
x + (x+8) = 50
Combine x's
 
2x + 8 = 50
subtract 8 from both sides
 
2x = 42
Divide both sides by 2
 
x = 21
 
Solve for y
 
y = 21 + 8 = 29
 
The two numbers are 21 and 29.
 
 
Hi Nazel;
FIRST...x
SECOND...x+8
(x)+(x+8)=50
x+x+8=50
2x+8=50
Let's subtract 8 from both sides...
-8+2x+8=50-8
2x=42
Let's divide both sides by 2...
(2x)/2=42/2
x=21
FIRST...21
SECOND...21+8=29
21+29=50