solve algebraic equations

## the sum of two number is 50.the second number is 8 more than the first number

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# 3 Answers

Let the first number be x. Then:

the second number becomes x+8.

Set up an equation: x+(x+8)=50 => 2x+8=50 => 2x=42 => x=21 => this is the first number (because this is what we set equal to x)

Second number = x+8 => 21+8=29

Two unknowns x and y.

Using information from the problem

x + y = 50 Sum of two numbers is 50

y = x + 8 The second number is 8 more than the first number.

Replace y in first equation

x + (x+8) = 50

Combine x's

2x + 8 = 50

subtract 8 from both sides

2x = 42

Divide both sides by 2

x = 21

Solve for y

y = 21 + 8 = 29

The two numbers are 21 and 29.

Hi Nazel;

FIRST...x

SECOND...x+8

(x)+(x+8)=50

x+x+8=50

2x+8=50

Let's subtract 8 from both sides...

-8+2x+8=50-8

2x=42

Let's divide both sides by 2...

(2x)/2=42/2

x=21

FIRST...21

SECOND...21+8=29

21+29=50