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Physics Question

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1 Answer

First of all, by Newton's 2nd Law the net tangent force to the incline is:

F = ma = (15.0 kg)(0.271 m/s2) = 4.07 N.

The tangential and normal components of the force of gravity are:

Ft = mg sin 36° = (15 kg)(9.81 m/s2)sin  36° = 86.5 N

N =  mg cos 36° = (15 kg)(9.81 m/s2)cos 36° = 119 N

The net force is also given by F = Ft - µkN

To solve for friction force, equate the formula above with ma.

Ft - µkN = ma

Ff = µkN = Ft - ma = 86.5 N - 4.07 N = 82.4 N

Finally, the coefficient of kinetic friction is:

µk = Ff/N = (82.4 N) / (119 N) = 0.692