Harry Hotrod rounds a corner in his sports car at 50 km/h. The friction force holds him on the road. If he has twice the speed, what must be the friction force to prevent him from skidding off the road?
What must be the friction?
Tutors, please sign in to answer this question.
The friction must counteract (and equal) the outward acceleration defined by:
eq 1) a = v2/r
And the friction force can be found with
F= ma, subsituting eq 1) F=mv2/r
For this problem mass and radius are constants.
Let F1 equal the friction force at 50 km/h.
Let F2 equal the friction force at 100 km/h (2x50)
If we set this up as a ratio:
---- = -------
the m, r and v2 cancel from the equation and we are left with 1/4.
The friction force at 100 km/h must be 4 times larger than it was at 50 km/h.
Let f be the friction force. Apply Newton's second law towards to the center of the rotation.
f = mv^2/r, where f is the only force in centrilpetal direction.
If you double v, then f is quadripled.