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## What is the equation of a line with slope 3/4 and passing through (-1, -6). Write it in slope-intercept form.?

I am having problems on how to write this out and doing it can someone please help me math is not my strong point, thank you

You should recognize that you have been given a slope and an ordered pair which is a point consisting of an x and y coordinate.  You can use the Point-Slope equation for a linear line very easily by just plugging in these values.  y - (-6) = 3/4(x - (-1).  The next step is you need to solve for y.  Solving for y will put this in the desired slope-intercept form of a linear equation y = mx + b.  Remember you end up working with fractions so make sure you add/subtract after finding a common denominator.  The solution is y = (3/4)x - 21/4.
The equation is going to be of the form y=(3/4)x+something.  It passes through (-1,-6)
In order to walk to the y-axis from (-1,-6) you need to walk 1 step positive in x, from -1 to 0.
In order to stay on the line you must then walk up 3/4 step in y to -5 1/4=-21/4
y=(3/4)x-21/4

First we have the point slope formula:
y-y1=m(x-x1)     ................ equation1

Here in the given question, y1=-6 ,x1=-1
Plugging these values in equation 1
[y-(-6)]=3/4[x-(-1)]
y+6=3/4(x+1)
y+6=3/4x+3/4
y=3/4x-21/4