Search 74,513 tutors
FIND TUTORS
Ask a question
0 0

3/x+3 = 12x + 19/x^2 +7x+12 = 5/x+4 =

Tutors, please sign in to answer this question.

2 Answers

Hey Dawn,
 I'm going to assume the equation you are trying to solve is:
 
(3/(x+3)) - ((12x+19)/(x2+7x+12)) - ((5/(x+4)) =0
 
Notice that the quadratic factors into (x+4)(x+3) now using this as a common denominator gives"
 
3(x+4)-(12x+19)-5(x+3)/((x+4)(x+3)) = 0  expanding the numerator and collecting like terms gives
 
14x+22 = 0
 
so x=-22/14 or -11/7 and this satisfies the original equation
 
Regards
Jim
Dawn,
 
I'm sorry
 
Am I supposed to interpret the first term as
 
(3/x) + 3 or 3/(x + 3)?
 
How about the third term
 
(5/x) + 4 or 5/(x + 4)?

Seattle Equations tutors