how would you factor:

6x^2-x-2

x^2-3x+2x-6

81y^2-36

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how would you factor:

6x^2-x-2

x^2-3x+2x-6

81y^2-36

Tutors, please sign in to answer this question.

6x^2-x-2 = (3x-2)(2x+1), inverse foil

x^2-3x+2x-6 = x(x-3) + 2(x-3) = (x+2)(x-3), by grouping

81y^2-36 = (9y+6)(9y-6), using the difference of two squares formula

81x

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