How I find the domain of √(2x^{2}-7)? Please include all steps so I know what I'm doing, because I have no idea how to find the answer. Thanks!
Domain of sqrt(2x^2-7)?
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1 Answer
Hi again M;
√(2x^{2}-7)
As you already know, we cannot square root anything less than zero. We therefore must find the minimum value of 2x^{2}-7
0≤2x^{2}-7
7≤2x^{2}
7/2≤x^{2}
3.5≤x^{2}
√3.5≤x
-√3.5≥x Note the fact that because I multiplied the figure by a negative sign, I had to reverse the less than to greater than signage.
domain is (-∞, -√3.5]U[√3.5, +∞)
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