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find the distance . P1=(3,-3); P2=(1,4)

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2 Answers

Hi again Kevin;
a2+b2=c2
(x-x1)2+(y-y1)2=c2
  _______________
√[(x-x1)2+(y-y1)2]=c
   _____________
√[(3-1)2+(-3-4)2]=c
  ________
√(2)2+(7)2=c
  _____
√4+49=c
  __
√53=c
 
7.3=c
 

Comments

Thank you so much this class is doing a serious dance on my brain cells lol  I really appreciate your help Vivian
 
 
 
(3, -3) and (1, 4)
 
distance formula: √[ (x2 - x1)2 + (y2 - y1)2 ]
 
so,
 
√[(1 - 3)2 + (4 -(-3))2 ]
 
√[(-2)+ 72  ]
 
√(4 + 49) = √53