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Find the definite integral?

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2 Answers

the integral is sin-1(x/2) evaluated between 1 and 2 which is an angle whose sine is 1-an angle whose sine is 1/2 which is π/2-π/6=π/3
 
Regards
 
Jim
∫[4 - x2] dx = sin-1 (x/2) evaluated between 1 and 2
 
sin-1(2) - sin-1(1/2) = (1/3)pi
 

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The way you get arcsin(x/2)from ∫dx/√(4-x2)=∫dx/(2√(1-(x/2)2)=∫d(x/2)/(√(1-(x/2)2)
 

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