I need to know how to solve this question. How do you write a polynomial function of least degree with integral coefficients that has the given zeros. Problem: 3-2i Thank you! Nov 10 | Cynthia from Hermitage, TN | 2 Answers | 0 Votes Mark favorite Subscribe Comment
If 3-2i is a zero of a polynomial with integer coefficients, then the conjugate 3+2i must also be a zero of this polynomial. Therefore, the polynomial is at least quadratic (degree 2): (x - (3-2i))(x - (3+2i)) = x² -6x + 13 Nov 10 | Andre W. Best answer Comment Comments Thnak you so much! Nov 10 | Cynthia from Hermitage, TN Comment
Cynthia, are you sure there's not more to this question? What degree is the polynomial supposed to be? Nov 10 | William S. Comment
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