(6t^{3}+5t^{2}+9)÷(2t+3)
(6t^3+5t^2+9)/(2t+3)
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2 Answers
3t^2 - 2t + 3
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2t+3 |6t^3 +5t^2 + 0t + 9
-(6t^3 + 9t^2)
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-4t^2 + 0t
- (-4t^2 - 6t)
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6t + 9
-(6t+9)
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0
Answer:
3t^2 - 2t + 3
use long division
divide 2t into 6t^3 and get 3t^2
multiply 3t^2 times 2t+3 and get 6t^3+9t^2
subtract 6t^3+9t^2 from 6t^3+5t^2 and get -4t^2; now bring down the 9 and you have -4t^2+9
divide 2t into -4t^2 and get -2t
multiply -2t times 2t+3 to get -4t^2-6t
subtract -4t^2-6t from -4t^2+9 to get 9+6t or 6t+9
divide 2t into 6t to get 3
3 times 2t+3 gives you 6t+9
subtract to get 0
answer:3t^2-2t+3