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solve for x :3^x+3^x+1=36

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1 Answer

if this was the equation:
3x+3x+1=36
 
 
then:
2(3x) +1=36
2(3x)=35
3x=35/2
x=log3(35/2)
x=log3(35) - log3(2)
 
 
if this was the equation:
3x + 3x+1 = 36
 
then:
3x + 3(3x) = 36
3x(3+1) = 36
3x = 36/4 
3x = 9
x = log39
x=2
 
(since this is a much nicer answer, I'm inclined to believe this is what you meant)

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